LeetCode 1389. 按既定顺序创建目标数组---村雨遥

题目1389. 按既定顺序创建目标数组[1]描述示例 1： 输入：nums = [0,1,2,3,4], index = [0,1,2,2,1] 输出：[0,4,1,3,2] 解释： nums index target 0 0 [0] 1 1 [0,1] 2 2 [0,1,2] 3 2 [0,1,3,2] 4 1 [0,4,1,3,2] 示例 2： 输入：nums = [1,2,3,4,0], index = [0,1,2,3,0] 输出：[0,1,2,3,4] 解释： nums index target 1 0 [1] 2 1 [1,2] 3 2 [1,2,3] 4 3 [1,2,3,4] 0 0 [0,1,2,3,4] 示例 3： 输入：nums = [1], index = [0] 输出：[1]解题思路因为数组在不断变化，所以新建一个列表list，作为存储不断变化的“数组”；对nums和index从左到右依次读取，利用列表的add()方法，将下标 index[i] 处插入值 nums[i]；因为最终返回值是int数组，所以新建一个int数组target；将list转换为target；返回target;实现package Array; import java.util.ArrayList; /** * Created with IntelliJ IDEA. * Version : 1.0 * Author : cunyu * Email : cunyu1024@foxmail.com * Website : https://cunyu1943.github.io * Date : 2020/3/26 10:55 * Project : LeetCode * Package : Array * Class : OneThreeEightNine * Desc : 1389. 按既定顺序创建目标数组 */ public class OneThreeEightNine { public static void main(String[] args) throws Exception { OneThreeEightNine oneThreeEightNine = new OneThreeEightNine(); int[] nums = {0, 1, 2, 3, 4}; int[] index = {0, 1, 2, 2, 1}; for (int item : oneThreeEightNine.createTargetArray(nums, index) ) { System.out.println(item); } } public int[] createTargetArray(int[] nums, int[] index) { ArrayList<Integer> list = new ArrayList<>(); for (int i = 0; i < nums.length;i++){ list.add(index[i],nums[i]); } int[] target = new int[nums.length]; for (int i = 0; i < list.size(); i++) { target[i] = list.get(i); } return target; } }参考资料

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1389. 按既定顺序创建目标数组: https://leetcode-cn.com/problems/create-target-array-in-the-given-order/

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